Balance the equation
2S+3O2=2SO3
300 ml is the same as 0.3 litres
thus the moles per volume and ideal pressure will be
n(SO3)=V(SO3)/Vm=0,3/22,4=0.013mol
multiply by 3 due to volume ratio to get the number of moles of oxygen.
n(O2)=0.013*3/2=0.0195mol
multiply by ideal pressure volume of gases at room temperature to get the volume of oxygen required.
V(O2)=0.0195×22,4=0.437l=437ml
therefore volume is approximately 437ml
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