1. Arrange s, p and d sub-shells of a shell in the increasing order of effective nuclear charge (Zeff) experienced by the electron present in them.
2. Nickel atom can lose two electrons to form Ni2+ ion. The atomic number of nickel is 28. From which orbital will nickel lose two electrons.
3. Calculate the total number of angular nodes and radial nodes present in 3porbital.
1. order for effective nuclear charge : s>p>d because s is closest to nucleus so it has maximum attraction from nucleus while d is far from nucleus so it feel less attraction from nucleus.
2 Atomic number of Ni is 28 and its electronic configuration is "1s^22s^22p^63s^23p^63d^84s^2."
So Ni will lose electron from 4s orbital.
3. no. of radial nodes = n-l-1
for 3p; n= 3 and l = 1 for p-orbital
So no. of radial nodes = 3-1-1 = 1
no. of angular nodes = l = 1
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