Answer to Question #126770 in General Chemistry for Lin

Question

How many grams of barium sulfate can be made from 2.00 grams of barium chloride?

BaCl2(aq) + Na2SO4(aq)→ BaSO4(s) + 2NaCl(aq)

Answer 1

Molar Mass of BaCl₂ = 208.23 g/mol .

Mole of BaCl₂ = 2.00 grams of barium chloride / 208.23 g/mol ;

So , Moles of BaCl₂ = 0.0096 mole

1 mol. of BaCl₂ gives 1 mol. of BaSO₄

So , Mole of BaSO₄ formed = 0.0096 mole .

So , Mass of BaSO₄ = Mole of BaSO₄ * Molar Mass of BaSO₄ .

So , Mass of BaSO₄ = 0.0096 mole * 233.38 g/mol = 2.240 g . Answer .