Question #126160
A sample of limestone, CaCO3 was sealed inside a strong glass tube. The mass of the tube and limestone was found to be 156.4g. The tube was then heated over a Bunsen burner, causing the formation of some quicklime, CaO and carbon dioxide gas?
1
Expert's answer
2020-07-13T07:21:38-0400

When CaCO3CaCO_3 is strongly heated, it undergoes thermal decomposition to form CaOCaO and CO2CO_2

The equation for the reaction is as follows;

CaCO3CaCO_3 (s)_{(s)} \to CaO(s)CaO_{(s)} ++ CO2(aq){CO_2}_{(aq)}

The mass of the products after the reaction is not affected by the reaction hence the products mass remains at 156.4g156.4g after the reaction.


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