Let minimum volume of 12.00 M hydrochloric acid would be required to completely dissolve a 500.00 g iron (Fe) . is " V" liter .
So , Moles of HCl = ( V * 12 ) mole = 12 V mole ..................1.
Moles of Fe = Mass of Fe / Molar Mass of Fe = 500 / 56 = 8.92857 . mole .
Given Reaction is
Fe(s) + 2HCl(aq) ⇨ FeCl2(aq) + H2(g) ..............
1 mole of Fe Completely React With 2 mole of HCl.
8.92857 mole of Fe Completely React With ( 2*8.92857 ) = 17.85714 mole of HCl..............
So moles of HCl Reacted = 17.85714 mol. ..............................2..
From 1 and 2 Both are Represent Moles of HCl in This Reaction So Both Should Be Equal .
12 V mole = 17.85714 mole
V =17.85714 / 12 . = 1. 488 liter .
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