We need to find amount of substance n=NNAn=\frac{N}{N_A}n=NAN and then multiply it by oxygen molar mass
m=NNAM=6×10236.02×1023mol−1×32gmol≈31.89gm = \frac{N}{N_A}M = \frac{6\times10^{23}}{6.02\times10^{23}mol^{-1}}\times32\frac{g}{mol} \approx 31.89gm=NANM=6.02×1023mol−16×1023×32molg≈31.89g
(What Avogadro constant value do you use? If it's 6*10^23 the answer would be 32g)
Answer: 31.89g
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