We need to find amount of substance "n=\\frac{N}{N_A}" and then multiply it by oxygen molar mass
"m = \\frac{N}{N_A}M = \\frac{6\\times10^{23}}{6.02\\times10^{23}mol^{-1}}\\times32\\frac{g}{mol} \\approx 31.89g"
(What Avogadro constant value do you use? If it's 6*10^23 the answer would be 32g)
Answer: 31.89g
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