Answer to Question #124428 in General Chemistry for Vansh

Question

In an experiment, to determine the percentage purity of the hydrochloric acid, 25cm3 of the acid solution made by dissolving 25.5g of impure acid in a liter of solution was found to neutralize 25cm3 of 0.4M NaOH solution. Calculate
a. Concentration of the acid in
(i) g/dm3
(ii) mol/dm3
b. percentage purity of the acid
c. percentage impurity of the acid
d. What mass of impurities contained in 25.5g?

Answer 1

V₁S₁=V₂S₂        Here, V₁= 25 cm³, V₂=25 cm³, S₂= 0.4 M

S₁ = (25×0.4) /25 M

    =0.4 M

Strength of the acid is 0.4 mol / dm³

m = n×M              Here, n= 0.4 mol / dm³, M= 36.46 g/mol

  = 0.4×36.46 g / dm³

   =14.584 g / dm³

a)

i) Concentration of the acid is 14.584 g / dm³ (Answer)

ii) Concentration of the acid is 0.4 mol / dm³ (Answer)

b)

percentage purity of the acid = (14.584/25.5) ×100

                                             = 57.19 percent (Answer)

c)

percentage impurity of the acid = 100-57.19 = 42.81 percent (Answer)

d)

mass of impurities contained in 25.5g = 25.5-14.584 g

                                                                  =10.916 g (Answer)