Question

A metal cube with a mass of 55grams at temperature of 85°C is immersed in 150grams of water at temperature of 20°C. The metal and water then reach a final temperature of 23oC. How much heat does the water gain?


Specific heat of water, which is 4.184 J/gC.

Answer 1

heat loss by metal = heat gained by water

m₁C(∆T₁) = m₂C(∆T₂)

heat gained by water= m₂C(∆T₂)

= 150*4.184*( 296-293)

=150*4.184*3

= 1882.8 joules