Given % Of Carbon = 40.67 ;
% Of Hydrogen = 5.085 ;
% Of Oxygen = 54.245 ;
% mole Of Carbon = 40.67 /12 = 3.390 .
% mole Of Hydrogen = 5.085 /1 = 5.085 .
% mole Of Oxygen = 54.245 /16 = 3.390 .
Molar ratio Of Carbon : Hydrogen : Oxygen . = 3.390/3.390 : 5.085 /3.390 : 3.390 /3.390 :
Molar ratio Of Carbon : Hydrogen : Oxygen . = 1 : 1.5 : 1 .
Integral Molar Ratio = 2 : 3 : 2 .
So Empirical Formula = C2H3O2 ; ANSWER.
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