Answer to Question #123884 in General Chemistry for K'onta Davis

Question #123884

112,300 joules heat is transferred when 240 g of a metal sample is cooled from 880 degrees celsius to 13 degrees celsius. What is the specific heat?

Expert's answer

q = cmΔT => c = q / mΔT = 112300J / (240g x (880^oC - 13^oC)) = 0.54 J/g^oC

Answer: c = 0.54 J/g^oC

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