Answer to Question #123638 in General Chemistry for karina

Question

Calculate the following Hrxn of N2 (g) + O2 (g) → 2 NO (g) Given: 2/3NO (g) → 1/3 N2 (g) + 1/3O2 (g) H°rxn = -5214

Answer 1

12N₂(g) + O₂(g) → NO₂(g), ΔH^∘_A = 33.2 kJ

12N₂(g) + 1/2 O₂(g) → NO(g), ΔH^∘_B = 90.2 kJ