Answer to Question #123618 in General Chemistry for kelly

Question #123618
Product A consists of 20% phosphoric acid, 12% sodium polyacrylate, 15% potassium pyrophosphate and 53% water (all wt%). There are 1,500 LBS of product A in stock.
It has been decided that Product A would be eliminated from the company's product line and replaced with Product B.
Product B consists of 3% zinc sulfate, 25% phosphoric acid, 8% sodium polyacrylate and 19% potassium pyrophosphate (all wt%).
We want to make 4000 LBS of product B, and we want to use Product A as a base since it already contains most of the ingredients. How many LBS of the following ingredients do we need to add to 1500 LBS of Product A in order to make 4000 LBS of product B?
a. Zinc Sulfate
b. Phosphoric Acid
c. Sodium Polyacrylate
d. Potassium Pyrophosphate
e. Water
1
Expert's answer
2020-06-23T02:15:36-0400


a. Zinc Sulfate is not in A, so we need 120 lbs of it (4000 lbs x 3 % / 100%).


b. Phosphoric Acid: 1000 lbs required (4000 lbs x 25 % / 100%) and we have 300 lbs from A (1500 lbs x 20 % / 100%). So 1000 lbs - 300 lbs = 700 lbs is needed to add only.


c. Sodium Polyacrylate: 320 lbs is required (4000 lbs x 8 % / 100 %), and we have 180 lbs from A (1500 lbs x 12 % / 100%). So 320 lbs - 180 lbs = 140 lbs is needed to add.


d. Potassium Pyrophosphate: 760 lbs is required (4000 lbs x 19 % / 100 %), and we have 225 lbs from A (1500 lbs x 15 % / 100%). So 760 lbs - 225 lbs = 535 lbs is needed to add.


e. Water: the total mass of water in B is 4000 - (120 + 1000 + 320 + 760) = 1800 lbs. And we have 795 lbs from A (1500 lbs x 53 % / 100%). So 1800 lbs - 795 lbs = 1005 lbs is needed to add.



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