Question

If the pressure in a cylinder of carbon dioxide at 34°C increases from 1.02 atm to 1.34 atm what is the new temperature of the gas?

Answer 1

Solution.

$T_1=34^oC=307K;$

$P_1=1.02atm;$

$P_2=1.34atm;$

$V=const;$

$\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}\implies$ $T_2=\dfrac{T_1P_2}{P_1};$

$T_2=\dfrac{307K\sdot1.34atm}{1.02atm}=403K=130^oC;$

Answer: $T_2=130^oC.$