Let's write ideal gas law
pV=mRTMM=mRTpV=5.1×10−5kg∗8.31Jmol∗K∗323K1.02×105Pa∗6.64×10−5L≈2.02×10−2kgmol=20.2gmolpV = \frac{mRT}{M} \\ M = \frac{mRT}{pV} = \frac{5.1\times10^{-5}kg *8.31\frac{J}{mol*K}*323K}{1.02\times10^5Pa*6.64\times10^{-5}L} \approx 2.02\times10^{-2}\frac{kg}{mol} = 20.2\frac{g}{mol}pV=MmRTM=pVmRT=1.02×105Pa∗6.64×10−5L5.1×10−5kg∗8.31mol∗KJ∗323K≈2.02×10−2molkg=20.2molg
In the periodic table it's the molar mass of neon
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