1)Na=23
O=16
H=1
Molar mass ==23+16+1=23+16+1=23+16+1 =40
2)Fe=55.8
S=32
Molar mass=(55.8×2)+(32×2)+((16×4)×3)( 55.8\times2 )+(32\times2)+ ((16\times4)\times 3)(55.8×2)+(32×2)+((16×4)×3) =399.6
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