CaC2+2H2O=C2H2+Ca(OH)2
1.The amount of C2H2 can be found by the following Mendeleev-Clapeyron equation:
n=P*V/R*T where R is equal to 8.31
n=99.5*0.935/8.31*290 =0.0386mol
Comment: 290 is the temperature in Kelvin. To find this, 273 degrees Celsius is added
2.According to the above reaction, 0.0386 mol of C2H2 is formed from as many moles of CaC2. Hence 0.0386mol(2.4704gr) CaC2 was reacted
3.determine the percentage of CaC2 unit in the starting material. To do this, the mass of CaC2 is divided by the mass of the total substance and multiplied by 100%
2.47/9.37=0.26365*100%=26.365%
Answer: 26.365%
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