Answer to Question #122861 in General Chemistry for FRANCIS KAMARA

Question

Aluminum reacts with bromine to form aluminum bromide:



2 Al + 3 Br2  2 AlBr3



if 48 grams of Al and 100 g of Br2 are reacted, how much AlBr3 can be produced

Answer 1

E(Al)=48/(2*27)=0.889;

E(Br₂)=100/(160*3)=0.208;

Br₂ is the limitant reactant

m(AlBr₃)=100*2*267/480=111.25 g;

Answer: 111.25 g of AlBr3 can be produced