Answer to Question #122802 in General Chemistry for Sumanth Bajjuri

Question

Calculate the reduced mass of HF molecule in kg.

Answer 1

Reduced mass $\mu=$ m₁m₂/(m₁+m₂)

for HF m₁=1g and m₂= 19g

so $\mu=$ $1*19/(1+19)$

$\mu$$=19/20 g$