Question

The reaction between hydrochloric acid and aluminum produces hydrogen gas and aluminum chloride. How many moles of H2 can be obtained when 3.80 mol HCl reacts with an excess of Al ?

6HCl+2Al⟶3H2+2AlCl3

Answer 1

The balanced equation of the reaction is

6HCl+2Al$\to$ 3H₂+2AlCl₃

Mole ratio is $6:2 \to3:2$

$3.80 mol HCl *\dfrac{3 mol H2}{6 mol HCl}=1.9$

$=1.9 mol H2$