Answer to Question #122334 in General Chemistry for John Banks

Question

1. What is the new [H2SO4], if 350.0mL of 6.00M H2SO4 is diluted with 570.0mL of water?


2.What is the new MnSO4 concentration, if 25.0mL of 1.45M solution is diluted to 1.00L?

Answer 1

Question 1

When a substance is diluted the number of moles of the solute remains the same..Therefore, the following expression is used

$C$₁$V$₂ $=C$₂$V$₂

Thus,

$C2=\dfrac{C1V1}{V2}$

$=\dfrac{6.mol.L^{-1}*350mL*10^{-3}.L.mL^{-1}}{570 mL*10^{-3}.L.mL^{-1}}$

$C2$ $=3.68M$

Question 2

We use the following expression

$C1V1=C2V2$

Thus

,$C2=\dfrac{C1V1}{V2}$

$=\dfrac{1.4M*0.025L}{1.0.L}$

$C2=0.035M$