H₃O⁺
pH=−lg[H3O+]=−lg[3.2∗10−6]=5.495pH=-lg[H_3O^+]=-lg[3.2 *10^-6]=5.495pH=−lg[H3O+]=−lg[3.2∗10−6]=5.495
Answer: pH=5.495pH=5.495pH=5.495
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments