H2A+2NaOH=Na2A+2H2O
1.we find the amount of NaOH. to do this, we multiply the concentration by the volume (liters)
0.015 litres * 0.3 mol/litres=0.0045 mol
2.based on the above reaction we can find the amount of H2A. for this we divide the amount of naoh by 2
0.0045mol /2=0.00225mol
3.now we find the molar mass of H2A. To do this, we divide the mass of H2A by the amount of matter: M=m/n=0.12g/0.00225mol=53.33g/mol≈53g/mol
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