Question

In a particular experiment, a 12.2 g sample of N2 reacts completely. The mass of Mg3N2 produced is.

Answer 1

3Mg+N2=Mg3N2

$n(N2)=\frac{m}{M}=\frac{12.2}{28.014}=0.43$

N2 in shortage

n(Mg3N2)=0.43

$m=M\times M=0.43\times100.9290=43.40$