Answer to Question #121646 in General Chemistry for Cass

Question

17.5 ml of KOH requires 12.5 ml of 0.25 M HCl. Find M for KOH

Answer 1

KOH+HCl=KCl+H2O

V (KOH)=0.0175L

nKOH=nHCL

$n=0.25\times0.0125=0.003125$

$M=\frac{0.003125}{0.0175}=0.1786$