Answer to Question #121645 in General Chemistry for Cass

Question

d. 35.0 ml of H2SO4 requires 20.0 ml of 0.100M NaOH. Find M for H2SO4.

Answer 1

d)Equation for the reaction:

$2NaOH_{aq}+{H_2SO_4}_{aq}- {Na_2SO_4}{aq}+2H_2O_{l}$

$2$ mol of $NaOH$ reacts with $1$ mol. of $H_2SO_4$

Mol $NaOH$ in $20.00ml$ of $0.100M$ solution $=$ $20mL\over1000mL$ $* 0.100M$

$=2.0*10^{-3} mol$

This reacts with ${2.0*10^{-3}}\over2$ $=$ $1.0*10^{-3}$ $mol$

$\therefore$ $35mL$ of $H_2SO_4$ solution contains $1.0*10^{-3}$ mol of $H_2SO_4$

$1.0L$ $=1000mL$ solution contains;

$1000mL\over 35mL$ * $1.0*10^{-3}mol$ $=0.0286 mol$

Molarity of $H_2SO_4$ $=0.0286M$