Question

Buffer solution was created containing 1.00M acetic acid and 0.500M sodium acetate. The Ka of acetic acid is 1.77x10^-5. What is the pH of the solution

Answer 1

pH of a solution is calculated using the formula below,

$pH=pKa+log\dfrac{[base]}{[acid]}$

$Ka=1.77 * 10^{-5}$

lets calculate pKa

$pKa=-logKa$

$=-log1.77*10^{-5}$

$=4.752$

therefore,

$pH=4.752+log\dfrac{[0.50]}{[1.00]}$

$=4.752-0.301$

$pH=4.451$