Answer to Question #121426 in General Chemistry for Cass

Question

17.5.0 ml of H2SO4 requires 20.0 ml of 0.150M NaOH. Find Molarity for
H2SO4.

Answer 1

Solution.

$V(H_2SO_4)=17.5mL;$

$V(NaOH)=20.0mL;$

$M(NaOH)=0.150M;$

$M(H_2SO_4)-?;$

Because the reaction is a 1:1 rxn ratio, it is useful to apply

 

(Molarity x Volume)Acid = (Molarity x Volume)Base;

$M(H_2SO_4)V(H_2SO_4)=M(NaOH)V(NaOH)\implies$

$M(H_2SO_4)=\dfrac{M(NaOH)V(NaOH)}{V(H_2SO_4)};$

$M(H_2SO_4)=\dfrac{0.150M\sdot 20.0mL}{17.5mL}=0.171M;$

Answer: $M(H_2SO_4)=0.171M.$