Let's calculate the concentration by formula
M1V1=M2V25×0.05=M2×100M2=2.5×10−3M_1V_1=M_2V_2\\5\times0.05=M_2\times100\\M_2=2.5\times10^{-3}M1V1=M2V25×0.05=M2×100M2=2.5×10−3
moles of CuSO4 in 10 ml of this solution = 2.5×10−3×10=0.025moles2.5\times10^{-3}\times10=0.025 moles2.5×10−3×10=0.025moles
molar mass of copper sulphate = 159.6 grams
mass of copper sulphate here = 159.6×\times× 0.025=4 grams
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