Question

you must prepare a 100mL solution of hydrochloric acid with a concentration of 0.500mol/L. You are given the appropriate glassware and a bottle of 2.50mol/L stock hydrochloric acid. What volume of stock solution must you use to prepare the solution?

Answer 1

V₁ - ?; С₁ = 2.50 mol/L, C₂ = 0.500 mol/L, V₂ = 0.100 L

C₁ = n/V₁ ; С₂ = n/V₂ $\implies$ C₁V₁ = C₂V₂

V₁ = C₂V₂/C₁ = 0.500*0.100/2.50 = 0.0200 L = 20.0 mL