Q = cmΔT
Q = 0.24 * 154.0 * (298 - 274) = 887.04 J
M (Ag) = 107.87 g/mol
C = 0.24 J/°C·g - for 1 g of Ag
For 107.87 g (1 mol):
0.24 * 107.87 = 25.89 J/°C·mol
m = Q / cΔT
ΔT = 14.8 - 11.3 = 3.5
m = 1.27∗1000/(0.24∗3.5)1.27*1000 / (0.24 * 3.5)1.27∗1000/(0.24∗3.5)
m = 1511.9 g