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Answer to Question #120468 in General Chemistry for Jesse Banks
Question #120468
The volume in liters of oxygen gas if it has a mass of 2.67 grams
Expert's answer
n (O2) = 2.67g / 32.00g/mol = 0.0834 mol
At STP 1 mole of a gas occupies the volume of 22.4 L (VM = 22.4 L/mol). Therefore,
V (O2) = VM x n(O2) = 22.4 L/mol x 0.0834 mol = 1.87 L.
Answer: 1.87 L
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