Answer to Question #120468 in General Chemistry for Jesse Banks

Question

The volume in liters of oxygen gas if it has a mass of 2.67 grams

Answer 1

n (O₂) = 2.67g / 32.00g/mol = 0.0834 mol

At STP 1 mole of a gas occupies the volume of 22.4 L (V_M = 22.4 L/mol). Therefore,

V (O₂) = V_M x n(O₂) = 22.4 L/mol x 0.0834 mol = 1.87 L.

Answer: 1.87 L