Answer to Question #120269 in General Chemistry for queen

Question

How many moles of iron (III) oxide will be produced if 500g of iron reacts in the following equation?

Answer 1

4Fe(s)+3O2(g)→2Fe2O3(s)

Mole ratio= 4:2

1 mol of Fe =56g

500/56 = 500g

= 8.92857 moles

Mole ration =4:2

0.67 moles = 8.92857

0.33 moles = ( (0.33)(8.92857))/0.67

= 4.464285 moles