Question

1. The instructions for a solution ask you to put 15.0 grams of HCl (strong) into 2.0L of water solution, what is the expected pH of the solution?

Answer 1

The molarity becomes;

$Molarity= mass/rfm$

Molarity=15/36.46=0.41 M

$PH=-log(0.41)$

PH=3.8