Answer to Question #119872 in General Chemistry for queen

Question

when placed in water, sodium dichromate will dissociate in the following equation:
Na2Cr2O7 ---> 2Na + Cr2O7^2-

If the concentration of sodium dichromate is initially 0.127 mol/L, what will be the concentration of the sodium ion?

Answer 1

From 1 mole of Na2Cr2O7 , 2 moles of Na+ ion forms

so from 0.127 moles of Na2Cr2O7 , 2* 0.127 = 0.254 moles of Na+ ion will be formed

and concentration of Na+ will be 0.254 mole/ l