Answer to Question #119621 in General Chemistry for Taylor

Question

Dr. Suzanne acquires a quantity of a 923ppm sodium chloride solution (solution a) Dr Suzanne takes a small volume of solution A and adds a bunch of water to it. This dilution solution (Solution B) has a concentration of 175 ppm. Dr Suzanne forgot what volume she used, so she makes a plan to find it, she reacted all of Solution B with excess Lead II Nitrate solution, producing 0.399g of precipitate. Using the information The volume of Solution A used to prepare solution B is?

Answer 1

Pb(NO3)2 + 2NaCl= 2NaNO3 + PbCl2.

117 x 0.399/278 = 0,167924461 g of NaCl.

And 175 mg/L.

167.92446 mg/175 mg/L= 0,959568343 L. Solution B.

167.92446mg/923 = 0,181933326 L. Solution A.