Answer to Question #119151 in General Chemistry for Abigail Rouse

Question

A system at equilibrium is represented by the following chemical equation: N₂(g) + 3H₂(g) <--> 2NH₃(g) At a given temperature, 1.40 moles of N₂, 0.888 moles of H₂, and 3.17 * 10⁻⁸ moles of NH₃ are in the 4.00 L vessel that reaches equilibrium. Calculate the value of K for the system.

Answer 1

Concentration of N₂ at equilibrium =

1.40 / 4 = 0.35 mole / litre.

Concentration of H₂ at equilibrium =

0.888 / 4 = 0.222 mole / litre.

Concentration of NH₃ at equilibrium =

3.17 × 10 ^-8 / 4 = 0.7925 × 10^-8 mol / litre.

= 7.9 × 10 ^{- 9} mol/ litre.

Equilibrium CONSTANT for reaction =

(Concentration of NH₃)²

/(Concentration of N₂)×(Concentration of H₂)³.

So, equilibrium constant =

( 7.9 × 10^-9 )² / (0.35 ) × (0.222)³ .

Equilibrium CONSTANT = 16297.7 × 10^-18 ..

Equilibrium Constant = 1.6297733 × 10^-14....^.