Question

What amount of H2O is present when it takes 8328 joules to boil water to steam at 100 °C

Answer 1

Heat of vaporization of water $H_v = 2260 \frac{J}{g}$

$q=m \times H_v$

$m=\frac{q}{H_v}= \frac{ 8328 J}{2260 \frac{J}{g}}=3.685 g$