Answer to Question #118882 in General Chemistry for ced

Question

What is the molariity of a 50.0 mL aqueous solution containing 10.0 grams NaCl?

Answer 1

n (NaCl) = 10.0g / 58.44g/mol = 0.171mol

50.0mL of the solution contain 0.171mol of NaCl.

1000mL of the solution contain 1000×0.171 / 50.0 = 3.42mol of NaCl. Therefore, the molarity is 3.42M

Answer: 3.42M