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Answer to Question #118882 in General Chemistry for ced
Question #118882
What is the molariity of a 50.0 mL aqueous solution containing 10.0 grams NaCl?
Expert's answer
n (NaCl) = 10.0g / 58.44g/mol = 0.171mol
50.0mL of the solution contain 0.171mol of NaCl.
1000mL of the solution contain 1000×0.171 / 50.0 = 3.42mol of NaCl. Therefore, the molarity is 3.42M
Answer: 3.42M
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