Answer to Question #118860 in General Chemistry for queen

Question

you land a job as a laboratory assistant over the summer break. On your second day of your job, the laboratory technician asks you to prepare a 750 mL solution of potassium permanganate (KMnO4) that is 0.489 mol/L. What mass must you collect in order to prepare the solution?

Answer 1

c=n/V

n=V*c=0.750*0.489=0.367mol

M(KMnO₄)=39+55+16*4=158g/mol

m=n*M=0.367*158=57.97g

Answer: m=57.97g