Answer to Question #118689 in General Chemistry for madison

Question #118689

with the following chemical reaction, if we start with 6.81 grams of magnesium, how many litres of oxygen are required? 2Mg + O2 = 2MgO

Expert's answer

2Mg + O₂ = 2MgO

n(Mg) = 6.81/24 = 0.2838 mol

n(O₂) = n(Mg)/2 = 0.2838/2 = 0.1419 mol

V(O₂) = 0.1419*22.4 = 3.18 L

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