Question

Standardization of a sodium hydroxide solution against potassium acid phthalate (KHP) yielded the following data:
Wt. KHP (KHC8H4O4) = 0.8205 g
Volume of NaOH = 43.65 mL
(a) Calculate the Normality of NaOH solution.
(b) If the titer suggest 1ml NaOH = 1.02 mL HCl, what is the Normality of HCl solution?

Answer 1

a) 0.8205 x 43.65 /40 x 0.4365 = 2,05125 N.

b) 2.05125/1.02= 2,01102941.