Answer to Question #118637 in General Chemistry for Leah

Question

A container with an initial volume of 1.0L is occupied by a gas at a pressure of 150 kPa at 25oC. By changing the volume, the pressure of the gas increases to 600 kPa as the temperature is raised to 100oC. What is the new volume?

Answer 1

P₁ = 150 kPa

V₁ = 1.0 L

T₁ = 25^oC = 298 K

P₂ = 600 kPa

V₂ = unknown

T₂ = 100^oC = 373 K

Solution:

The Combined Gas Law:

P₁V₁/T₁ = P₂V₂/T₂

Cross-multiply to clear the fractions:

P₁V₁T₂ = P₂V₂T₁

Divide to isolate V₂:

V₂ = (P₁V₁T₂) / (P₂T₁)

Plug in the numbers and solve for V₂:

V₂ = (150 kPa × 1.0 L × 373 K) / (600 kPa × 298 K) = 0.313 L = 313 mL

V₂ = 313 mL

Answer: 313 mL is the new volume.