Solution.
"m=7g=0.007kg;"
"\\Delta t=10^oC;"
"Q=420J;"
The specific heat of a substance is the amount of heat that must be provided to a substance weighing 1 kg to heat it by 1oC.
"c=\\dfrac{Q}{m\\Delta t};"
"c=\\dfrac{420J}{0.007kg\\sdot10^oC}=6000\\dfrac{J}{kg^oC};"
Answer: "c=6000\\dfrac{J}{kg^oC};"
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