Solution.
m=7g=0.007kg;m=7g=0.007kg;m=7g=0.007kg;
Δt=10oC;\Delta t=10^oC;Δt=10oC;
Q=420J;Q=420J;Q=420J;
The specific heat of a substance is the amount of heat that must be provided to a substance weighing 1 kg to heat it by 1oC.
c=QmΔt;c=\dfrac{Q}{m\Delta t};c=mΔtQ;
c=420J0.007kg⋅10oC=6000JkgoC;c=\dfrac{420J}{0.007kg\sdot10^oC}=6000\dfrac{J}{kg^oC};c=0.007kg⋅10oC420J=6000kgoCJ;
Answer: c=6000JkgoC;c=6000\dfrac{J}{kg^oC};c=6000kgoCJ;
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