Solution.
pH=−log[H3O+]; [H3O+]=10−pH;
If pH=3.350;
[H3O+]=10−3.35=4.467⋅10−4M;
If pH=6.780;
[H3O+]=10−6.78=1.66⋅10−7M;
4.467⋅10−4−1.66⋅10−7=4467⋅10−7−1.66⋅10−7=4465.34⋅10−7=
=4.46534⋅10−4M;
Answer: concentration [H3O+] decreased by 4.46334⋅10−4M.
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