Answer to Question #118330 in General Chemistry for Narina Khalafyan

Question

. Calculate the [OH-] for a solution with a pH value of 10.28

Answer 1

pH+pOH=14

pOH = 14 − pH

pOH = 14 − 10.28 = 3.72

pOH=−log[OH⁻]

3.72 =−log[OH⁻]

10^−(3.72) = [OH⁻]

[OH⁻] = 10^−(3.72) = 0.00019 mol/L = 1.9 × 10⁻⁴ mol/L

Answer: 1.9 × 10⁻⁴ mol/L