Answer to Question #118328 in General Chemistry for Narina Khalafyan

Question #118328

Calculate the final pOH of a solution created by combining 125 mL of 2.50 M hydrochloric acid and 350 mL of 2.00 M sodium hydroxide.

Expert's answer

"POH= - log(OH-)"

HCl +NaOH =NaCl + H2O

125ml of 2.00M solution contain (125/1000)*2=0.25moles of NaOH

POH=-log(0.25)

POH= 6.0

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