Question #118028
The equilibrium constant for the formation of calcium carbonate from the ions in solution is 2.2x108 according to the reaction:

Ca2+(aq) + CO32-(aq) ⇄ CaCO3(s) K=2.2x108

What is the equilibrium constant of

2CaCO3(s) ⇄ 2Ca2+(aq) + 2CO32-(aq) K=?
1
Expert's answer
2020-05-24T16:31:54-0400

K=1/2.2x108


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