Answer to Question #117828 in General Chemistry for Jacob Barth

Question #117828

How many grams of sodium hydroxide would you need to produce 75 g of lead (II) hydroxide? 2 NaOH(aq) + Pb(NO3)2(aq) → 2 NaNO3(aq) + Pb(OH)2(s)

Expert's answer

n(Pb(OH)₂) = m/M = 75 g/241.21 g/mol = 0.31 mol

m(NaOH) = n*M = 2*n(Pb(OH)₂)*M(NaOH) = 24.8 g

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