Answer to Question #117642 in General Chemistry for Laura B Parton

Question

a steel tank contains 15.0 g of cl2 gas under a pressure of 5.0 atm at 22.0 degrees c what is the volume of the tank

Answer 1

P = 5.0 atm;

T = 22.0 °C = 295.15 K;

M(Cl₂) = 70.906 g/mol;

n=m/M;

n(Cl2) = 15.0 g / (70.906 g/mol) = 0.211 moles;

Ideal gas law:

PV=nRT

V = (nRT)/P

Molar gas constant R=0.082058 L×atm/(K×mol)

V = (0.211 mol × 0.082058 L×atm/(K×mol) × 295.15 K) / 5.0 atm = 1.02 L

Answer: 1.02 L