Solution.
"C=5.2\\sdot10^{-3} mol\/L;"
"M(C_{27}H_{46}O)=386.65g\/mol;"
"V=4.7L;"
"m-?;"
"\\nu=\\dfrac{m}{M};\\implies m=\\nu\\sdot M;"
The molar concentration is calculated as follows:
"\u0421=\\dfrac{\\nu}{V} \\implies" "\\nu=C\\sdot V;"
"\\nu = 5.2\\sdot10^{-3}mol\/L\\sdot4.7L=24.44\\sdot10^{-3}mol;"
"m=24.44\\sdot10^{-3}mol\\sdot386.65g\/mol=9.45g;"
Answer: "m=9.45g."
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